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Grade 11 Specific Heat (Q = mcΔT) Worksheet with Answers

Grade 11 (US) · Year 12 (UK) · Class 11 (India) · Science

Unit 2: EnergyThermal EnergyNGSS HS-PS3-4

Calculating heat energy with Q = mcΔT. This free high school worksheet has 12 questions and a full answer key. Print it or save it as a PDF — every answer is checked by code, not guessed.

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Specific Heat (Q = mcΔT)

Grade 11 · Science

Score___ / 12

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Class

Date

Learning goal: Thermal Energy · NGSS HS-PS3-4

Directions: Read each question carefully and write your answer on the line. Use the diagram to help you.

Example

How much heat is needed to raise 20 g of iron by 40 °C? (c = 0.45 J/g·°C)

Answer: 360 J

RememberHeat energy

qmcΔTq = m × c × ΔTq = heat energy (J)c = specific heat (J/g°C)Water: c = 4.18 J/g°C
  1. 1

    1086.8 J of heat is added to 130 g of water (c = 4.18 J/g·°C). By how much does its temperature rise?

  2. 2

    How much heat is needed to raise 20 g of aluminum by 10 °C? (c = 0.9 J/g·°C)

    20 g aluminumq = ?c = 0.9 J/g°CΔT = 10 °Cq = m × c × ΔT
  3. 3

    4096.4 J of heat is added to 140 g of water (c = 4.18 J/g·°C). By how much does its temperature rise?

  4. 4

    140.4 J of heat is added to 120 g of copper (c = 0.39 J/g·°C). By how much does its temperature rise?

  5. 5

    1404 J of heat is added to 90 g of copper (c = 0.39 J/g·°C). By how much does its temperature rise?

    90 g copperq = 1404 Jc = 0.39 J/g°CΔT = ?q = m × c × ΔT
  6. 6

    2673 J of heat is added to 90 g of aluminum (c = 0.9 J/g·°C). By how much does its temperature rise?

    90 g aluminumq = 2673 Jc = 0.9 J/g°CΔT = ?q = m × c × ΔT
  7. 7

    How much heat is needed to raise 200 g of iron by 28 °C? (c = 0.45 J/g·°C)

    200 g ironq = ?c = 0.45 J/g°CΔT = 28 °Cq = m × c × ΔT
  8. 8

    19562.4 J of heat is added to 130 g of water (c = 4.18 J/g·°C). By how much does its temperature rise?

  9. 9

    How much heat is needed to raise 140 g of iron by 14 °C? (c = 0.45 J/g·°C)

    140 g ironq = ?c = 0.45 J/g°CΔT = 14 °Cq = m × c × ΔT
  10. 10

    5967 J of heat is added to 170 g of aluminum (c = 0.9 J/g·°C). By how much does its temperature rise?

    170 g aluminumq = 5967 Jc = 0.9 J/g°CΔT = ?q = m × c × ΔT
  11. 11

    6688 J of heat is added to 40 g of water (c = 4.18 J/g·°C). By how much does its temperature rise?

    40 g waterq = 6688 Jc = 4.18 J/g°CΔT = ?q = m × c × ΔT
  12. 12

    5760 J of heat is added to 200 g of aluminum (c = 0.9 J/g·°C). By how much does its temperature rise?

    200 g aluminumq = 5760 Jc = 0.9 J/g°CΔT = ?q = m × c × ΔT

★ Challenge corner for fast finishers

You are in a closed room with a candle, a match and a lamp. What do you light first?

How did I do?

Teacher's comments

Free printable worksheets with answer keys · aethelsystems.com/worksheets/science/11/specific_heat

Answer key (click to show)
  1. 1.2 °C
  2. 2.180 J
  3. 3.7 °C
  4. 4.3 °C
  5. 5.40 °C
  6. 6.33 °C
  7. 7.2520 J
  8. 8.36 °C
  9. 9.882 J
  10. 10.39 °C
  11. 11.40 °C
  12. 12.32 °C
  13. ★the match (challenge corner)

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