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Grade 9 Specific Heat (Q = mcΔT) Worksheet with Answers

Grade 9 (US) · Year 10 (UK) · Class 9 (India) · Physics

Unit 6: Going FurtherAdvanced: Physics II PreviewNGSS HS-PS3-4Advanced

Calculating heat energy with Q = mcΔT. This free high school worksheet has 12 questions and a full answer key. Print it or save it as a PDF — every answer is checked by code, not guessed.

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Specific Heat (Q = mcΔT)

Grade 9 · Physics

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Learning goal: Advanced: Physics II Preview · NGSS HS-PS3-4

Directions: Read each question carefully and write your answer on the line. Use the diagram to help you.

Example

How much heat is needed to raise 10 g of copper by 24 °C? (c = 0.39 J/g·°C)

Answer: 93.6 J

RememberHeat energy

qmcΔTq = m × c × ΔTq = heat energy (J)c = specific heat (J/g°C)Water: c = 4.18 J/g°C
  1. 1

    3159 J of heat is added to 90 g of aluminum (c = 0.9 J/g·°C). By how much does its temperature rise?

    90 g aluminumq = 3159 Jc = 0.9 J/g°CΔT = ?q = m × c × ΔT
  2. 2

    2430 J of heat is added to 100 g of aluminum (c = 0.9 J/g·°C). By how much does its temperature rise?

    100 g aluminumq = 2430 Jc = 0.9 J/g°CΔT = ?q = m × c × ΔT
  3. 3

    How much heat is needed to raise 100 g of copper by 21 °C? (c = 0.39 J/g·°C)

    100 g copperq = ?c = 0.39 J/g°CΔT = 21 °Cq = m × c × ΔT
  4. 4

    756 J of heat is added to 70 g of aluminum (c = 0.9 J/g·°C). By how much does its temperature rise?

    70 g aluminumq = 756 Jc = 0.9 J/g°CΔT = ?q = m × c × ΔT
  5. 5

    1673.1 J of heat is added to 130 g of copper (c = 0.39 J/g·°C). By how much does its temperature rise?

  6. 6

    How much heat is needed to raise 30 g of water by 40 °C? (c = 4.18 J/g·°C)

    30 g waterq = ?c = 4.18 J/g°CΔT = 40 °Cq = m × c × ΔT
  7. 7

    5472 J of heat is added to 190 g of aluminum (c = 0.9 J/g·°C). By how much does its temperature rise?

    190 g aluminumq = 5472 Jc = 0.9 J/g°CΔT = ?q = m × c × ΔT
  8. 8

    How much heat is needed to raise 140 g of copper by 35 °C? (c = 0.39 J/g·°C)

    140 g copperq = ?c = 0.39 J/g°CΔT = 35 °Cq = m × c × ΔT
  9. 9

    162 J of heat is added to 10 g of iron (c = 0.45 J/g·°C). By how much does its temperature rise?

    10 g ironq = 162 Jc = 0.45 J/g°CΔT = ?q = m × c × ΔT
  10. 10

    360 J of heat is added to 100 g of aluminum (c = 0.9 J/g·°C). By how much does its temperature rise?

    100 g aluminumq = 360 Jc = 0.9 J/g°CΔT = ?q = m × c × ΔT
  11. 11

    How much heat is needed to raise 80 g of water by 33 °C? (c = 4.18 J/g·°C)

    80 g waterq = ?c = 4.18 J/g°CΔT = 33 °Cq = m × c × ΔT
  12. 12

    612 J of heat is added to 40 g of iron (c = 0.45 J/g·°C). By how much does its temperature rise?

    40 g ironq = 612 Jc = 0.45 J/g°CΔT = ?q = m × c × ΔT

★ Challenge corner for fast finishers

If you could fold a sheet of paper 42 times, roughly how thick would it be?

How did I do?

Teacher's comments

Free printable worksheets with answer keys · aethelsystems.com/worksheets/physics/9/specific_heat

Answer key (click to show)
  1. 1.39 °C
  2. 2.27 °C
  3. 3.819 J
  4. 4.12 °C
  5. 5.33 °C
  6. 6.5016 J
  7. 7.32 °C
  8. 8.1911 J
  9. 9.36 °C
  10. 10.4 °C
  11. 11.11035.2 J
  12. 12.34 °C
  13. ★far enough to reach the Moon (about 440,000 km) (challenge corner)

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